The Lensmaker's Equation, 1/f = (n-1)(1/R₁ + 1/R₂), is derived using Snell's Law, trigonometry, and geometric relationships for a thin double convex lens, where f is the focal length, n is the refractive index of the lens material, and R₁ and R₂ are the radii of curvature of the two lens surfaces (positive for convex surfaces, negative for concave surfaces).
Derivation of Lensmaker's Equation | Optics Tutorial
Added:in the previous lecture we defined lens maker equation and we said we can use lens maker equation to determine the focal length of our lens knowing the index of refraction of that lens as well as the radi of curvature now let's actually derive the lens makers equation using geometry trigonometry and snail's law so let's suppose we have the following double con inex lens so we have the front surface of our lens and the back surface of the lens this line is the principal axis now Point C2 is the center of curvature of the back surface of our lens and point C1 is the rad or is the center of curvature of the front surface of our lens now this point f is the focal point of our lens let's suppose we take a single ray of light that is parallel to the axis when it hits the front surface it will refract when it hits the back surface it will refract once again and the final Ray the final refracted Ray will pass through the focal point because this Ray was parallel to our axis now let's suppose this point is the point where Ray hits our front surface and this line this black dashed line is the normal line to the surface at this point let's call that normal line one and likewise let's suppose this point represents the point where this in Array refracts and bends and so this line let's call it normal line two is the line that is normal to the back surface of our lens at this particular point now there are a lot of different angles involved in the following derivation so let's name all these angles so this angle is Theta 1 it's the angle between our ray of light and the normal line one now let's suppose this is our ray of light if we continue drawing our straight line as shown by the following dashed Line This Ray will actually refract it will bend and the angle between this black dashed line that is straight that runs along this Ray and the bended Ray is feta 7 so this angle is feta 7 now the angle between our normal line and our refracted Ray is Theta 2 now notice by the symmetry of the situation because the ray is parallel to the axis and this is a straight line Theta 1 is equal to this angle Theta 1 now theta 3 is given by this angle theta 3 is the angle between normal line two and the ray that passes inside our lens now feta 4 is given by the following angle Theta 4 is the angle between the normal line and this final refracted Ray angle five is given to be the angle between the axis and the normal line two and angle six is equal to the angle between the axis and this final refracted Ray so let's suppose that outside the lens we have air and the index of refraction of air is equal to N1 and that is equal to 1 now N2 represents the index of fraction of our lens now although the size of the double convex lens in this diagram is exaggerated so that the angle the angles are more clear we're making the assumption that our lens is a very thin lens and by making the assumption that the lens is a very thin lens we can approximate our angle to be approximately equal to S of that angle which is also approximately equal to tangent of that angle where angle is given in radians and not degrees now finally let's also Define the following two important parameters so the distance from this point where the ray hits the front surface to this axis is given by H1 and the distance from this point where the inray hits the outer uh region of our lens to this point to the axis this vertical distance is given by H2 so now let's begin our derivation and let's begin by recalling snail's law so recall that snail's law essentially gives us a relationship between the angle of incidence the angle of refraction and the indices of refraction for each one of our two mediums so let's begin with the following Ray so this Ray hits the surf surface and refracts so we're going to use Snell's law to build a relationship between Theta 1 and theta2 so N1 multiplied by S of theta 1 is equal to N2 multiplied by S of theta 2 so Theta 2 is the angle of refraction and Theta 1 is the angle of incident N1 is the index of refraction of air and N2 is the index of refraction C of our lens now let's make the assumption that N1 is equal to 1 so this cancels out now let's suppose N2 is equal to n so we replace our N2 with n to simplify our parameter now because of this assumption because we're assuming we're dealing with a very thin lens sine of theta is approximately equal to Theta so that means this be comes as follows so N1 disappears sine of theta 1 is replaced with Theta 1 and sine of theta 2 is replaced with Theta 2 and N2 is replaced with n so Theta 1 is equal to n multiplied Theta 2 now let's also uh use Snell's law for this Ray so let's suppose we're going from the outside to the inside so angle Theta 4 is our uh our angle of incidence and this angle theta 3 is the angle of refraction so N1 * s of theta 1 is equal to N2 * s of theta 2 now once again N1 is equal to 1 so this becomes 1 sine of theta 4 is approximately equal to Theta 4 S of theta 3 is approximately equal to theta 3 and N2 is replaced with n so we have the following two important relationships that we obtain by using Snell's law and making this assumption so this will become important in step four now let's move on to step two in our derivation and now let's use this approximation as well as trig function so we're using the S and tangent trig function so sine of theta 1 is equal to H1 / R1 1 so we're essentially examining a rectangle so let's suppose this H1 is the height of our rectangle this distance is the hypotenuse of our rectangle and this is the base of our rectangle now what exactly is the length of the base well it's the point from this location to C1 and because we're assuming we have a very thin lens the distance this distance simply represents our radius of curvature R1 so sine of theta 1 this angle is equal to opposite over hypotenuse and this distance represents our hypotenuse so sine of theta 1 is equal to H1 where H1 is this distance and R1 is the distance from point C1 to the front face of our lens now now this is approximately equal to Theta 1 because we're making the following assumption so R1 is the radius of curvature of the front surface now let's apply the same exact result for this triangle so we have this triangle where the height of the triangle is H2 and the hypotenuse of the triangle is R2 where R2 is the radius of curvature of the back surface of our lens so s of theta 5 is equal to H2 / R2 where this is approximately equal to Theta 5 by this approximation and finally we use tangent so we're using this triangle so we know this is our hypotenuse this is our uh length of the base and this is our height so once again we're using tangent function so tangent of this angle is equal to opposite divided by our base now this base is approximately equal to the focal length F so tangent of feta 6 is equal to H2 the height divided by the focal now what exactly is this well from this assumption we see that this is approximately equal to simply the angle Theta 6 so these three equations will become important just the moment in step four now finally let's move on to step three before we combine our results so in step three we're essentially using a bit of geometry so if we examine this diagram we get the following three relationships so we have angle Theta 7 is equal to Theta 1 minus Theta 2 angle Theta 4 is equal to angle Theta 5 + Theta 6 and Theta 5 is equal to Theta 3us Theta 7 now let's move on to step four in which we're going to combine these results to essentially derive lens Maker's equation so let's begin with the following equation from this last equation in step three feta 5 is equal to feta 3 minus feta 7 now what exactly is feta 3 let's go back to this equation from this equation we see feta 3 is equal to feta 4 / n so that's exactly what we plug in for feta 3 what about feta 7 feta 7 from this equation is equal to Theta 1 minus Theta 2 that's exactly what we plug in into this equation now let's actually distribute our negative so this becomes negative this becomes positive what exactly is feta 4 well from this equation feta 4 is equal to feta 5 + feta 6 let's replace feta 4 with with feta 5 plus feta 6 and let's actually distribute this end to both of these terms so that's exactly what we do in this step so feta 5 is equal to feta 5 / n plus feta 6 / nus feta 1 plus well now we want to represent 2 in terms of theta 1 so in this equation we see that Theta 2 is equal to Theta 1 / n and that's exactly what we do in this step now let's go back to this uh step step two from from step two we see that feda 5 is equal to H2 / R2 so we can replace feta 5 with H2 / R2 so this becomes H2 / R2 2 is equal to H2 / R2 ultied n plus what about Theta 6 well Theta 6 from this relationship is equal to H2 / f and that's exactly what we replace Theta 6 with what about Theta 1 from this relationship Theta 1 is equal to H1 / R1 so this becomes H1 / R1 and this becomes H1 / n multip multiplied by R1 now what is the relationship between H1 and H2 now in this diagram because of the exaggeration and size of our lens these two quantities do not look like they're equal however if the lens is very thin H1 is approximately equal to H2 so if H1 is approximately equal to H2 these quantities are the same so we can divide both sides by H and these will cancel out now let's also multiply both sides by n we get the following result so the N here cancels the N here cancels and the N here will cancel so n / R2 is = to 1 / R2 + 1 / f - n / R1 + 1 / R1 now if we rearrange our equation we now obtain lens Maker's equation we see that 1 / by the focal length is equal to n -1 multiplied 1 / R1 + 1 ided by R2 where n is the index of refraction of the lens f is the focal length of the lens R1 and R2 are the radi of curvature of our lens now R1 and R2 are positive as long as our lens is convex however if our lens is concave that means our radius of curvature will be negative
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