Analytic Continuation of the Riemann Zeta Function | Number Theory

Added:

Summation Setup
Integral Replace
Combining Terms
Zeta Formula
Refine Integral
Convergence Proof
Inequality Check
Continuation Done

Summation Setup

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Playing Section
  • 1

    Analyzes a specific partial sum to manipulate terms.

  • 2

    Uses summation by parts to relate sums and integrals.

  • 3

    Defines this as a stepping stone for the zeta function.

The classical definition of the Riemann Zeta Function as a Dirichlet series and its convergence properties for Re(s) > 1.
Fundamental concepts of Complex Analysis, specifically holomorphicity, analytic functions, and the uniqueness of analytic continuation.
Abel's Summation Formula (summation by parts), which is crucial for transforming discrete series into continuous integrals.
The behavior of complex exponents and improper integrals involving complex variables, such as the integral of x^(-s).
Analytic continuation of the Riemann Zeta Function to the entire complex plane (except for a simple pole at s=1) using the Gamma function.
The Functional Equation of the Riemann Zeta Function, which establishes a reflection formula relating zeta(s) to zeta(1-s).
The distribution of the zeros of the Riemann Zeta Function, distinguishing between trivial zeros and non-trivial zeros located within the critical strip (0 < Re(s) < 1).
The Riemann Hypothesis, which posits that all non-trivial zeros of the zeta function lie on the critical line Re(s) = 1/2.
The Prime Number Theorem, exploring how the analytic properties and non-vanishing of the zeta function on the line Re(s) = 1 dictate the distribution of prime numbers.
7.3K views106likes15:36@FematikaOriginal Release: 2017-11-09

The Riemann Zeta function ζ(z) can be analytically continued to all complex numbers with positive real part using the formula ζ(z) = 1/(z-1) + 1 + z × ∫₁^∞ [floor(t) - t] × t^(-z-1) dt, where the integral converges absolutely for Re(z) > 0 due to the bound |floor(t) - t| ≤ 1 and the estimation |∫₁^∞ [floor(t) - t] × t^(-z-1) dt| ≤ ∫₁^∞ t^(-Re(z)-1) dt = 1/Re(z).