x86 Operating Systems: BIOS Interrupt 0x10 to Print a Boot Message

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Setup
Print Function
Core Loop
Execution

Setup

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Playing Section
  • 1

    Initialize CPU registers to a consistent state.

  • 2

    Set stack pointer to start just after the bootloader code.

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    Prepare the segment registers for a clean execution environment.

Basic understanding of 16-bit x86 CPU architecture, including general-purpose registers (AX, BX, CX, DX) and basic assembly instructions like MOV.
Concept of the x86 boot sequence, including the role of the Master Boot Record (MBR) and the 512-byte boot sector limit.
Understanding of CPU execution modes, specifically 16-bit Real Mode in which BIOS execution takes place.
General concept of software interrupts and how the Interrupt Vector Table (IVT) maps interrupt calls to BIOS routines.
Handling user input in real mode using BIOS keyboard interrupts (such as INT 0x16).
Loading subsequent sectors of the operating system from disk into memory using BIOS disk interrupts (INT 0x13).
Transitioning from 16-bit Real Mode to 32-bit Protected Mode, including disabling BIOS interrupts and setting up the Global Descriptor Table (GDT).
Writing a multi-stage bootloader that loads a simple C-based kernel into memory and transfers execution control.
Direct memory-mapped I/O, such as writing characters directly to the VGA text mode frame buffer at address 0xB8000.
7.3K views205likes8:01@olivestemlearningOriginal Release: 2023-08-27

This video demonstrates how to modify a simple x86 bootloader to print a message on screen using BIOS interrupt 0x10 with AH=0x0e, which prints a character from AL register; the process involves initializing segment registers (DS, ES, SS) to zero, setting up the stack pointer at 0x7c00, defining a null-terminated string with DB, preserving registers (SI, AX, BX) on the stack, using LODSB to load characters, checking for the null terminator with OR AL, AL and JZ, and finally calling int 0x10 to print each character to the screen.